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Eof error python 3 input

input is designed to read until a newline character is sent. If you' re looking for a way to break out of the while loop, you could use CTRL+ D,. I' m guessing you are using Python 2 here not Python 3 as your tag suggests. In Python 2 input( ) waits for the user to enter some text and then tries to execute it. If you press ' Enter' input( ) will give an EOF error. I assume that is. The python 3 code: while True: a = [ ] s = input( ) if s = = ' - 1' : break else: # input for x in s. append( int( x) ) # count n = len( a) - 1 cnt = 0 for x in range( n- 1) : for y in range( x+ 1, n) : if a[ x] + a[ x] = = a[ y] or a[ x] = = a[ y] + a[ y] : cnt + = 1. 書籍に掲載されている簡単な条件分岐のプログラムを実行したのですが、 問題なく実行 される場合と、 下記エラーが. in < module> user = input( ' 気温は何度ですか? 実行は、 python3のパスをpyという名前でエイリアス登録し、. The problem is that multiprocessing.

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  • Video:Input python error

    Error python input

    Process explicitly closes stdin and opens / dev/ null, and the standard input is where input reads from. You might consider using subprocess or threads instead. You must close a try statement because you are declaring that there might be an error and you want to handle it while True: try: number = int( input( " what' s your favourite number? " ) ) print( number) break except ValueError as e: print( " Woah,. 1行にスペース区切りで複数の文字列の入力. A, B, Cは, いずれも 文字列.. def get_ input( ) : while True: try: yield ' '. join( raw_ input( ) ) except EOFError: break if _ _ name_ _ = = ' _ _ main_ _ ' : a = list( get_ input( ) ) # [ a1,. lst= [ ] while 1: try: x= int( input( ) ) lst. append( x) except EOFError: break print( type( lst), lst). 標準入力ならこれでどうぞ。. The problem is probably with this line elif: command = = '. ' The colon is in the wrong place, change it to elif command = = '. def get_ input( ) : while True: try: line = input( ) # Python 2.

    x で input( ) の挙動が異なるので注意 if line. 空行の場合、 line の中身は空文字列 break else: yield line except EOFError: break if _ _ name_ _ = = ' _ _ main_ _ ' : a.